Entropy: Why & How Does C_V Go to Zero?

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SUMMARY

Entropy is mathematically defined as S(A)=∫0T_AC_V(dT/T), where C_V represents the heat capacity at constant volume. As the temperature T_A approaches absolute zero, C_V must approach zero, aligning with the principles of the second law of thermodynamics, which states that the change in entropy (ds/dt) is always non-negative. In specific scenarios where the system is isolated and maintained at extremely low temperatures, C_V can decrease rapidly, leading to unique thermodynamic behaviors.

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  • Understanding of thermodynamic principles, particularly the second law of thermodynamics.
  • Familiarity with the concept of heat capacity, specifically C_V (heat capacity at constant volume).
  • Basic knowledge of calculus, particularly integration and limits.
  • Concept of absolute zero and its implications in thermodynamics.
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  • Study the behavior of C_V at low temperatures in materials science.
  • Investigate the mathematical derivation of entropy in different thermodynamic processes.
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Students and professionals in physics, thermodynamics researchers, and anyone interested in the fundamental principles governing entropy and heat capacity in physical systems.

matematikuvol
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Entropy is defined by:

S(A)=\int^{T_A}_0C_V\frac{dT}{T}

where A is state of the system in which temperature is T_A. When T_A\rightarrow 0 and C_V must go to zero. Why? And how fast does it go?
 
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Your question is technically right but entropy is always increasing so it never be fall in zero.The 2nd law of thermodynamics says that (ds/dt)≥ 0. But may be in some special cases if externally keep the temperature very low depends on the state of the system its true and this is a very speedy process that is no interaction between the system and its surroundings so that the temperature is nearly= 0 and Cv falls into zero...
 

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