This may be a dumb question, but:(adsbygoogle = window.adsbygoogle || []).push({});

Using the epsilon-delta definition of a limit, when x is approaching the maximum of a parabola, like with: [tex]\lim_{x\rightarrow0}-x^2[/tex], obviously any value of epsilon puts [tex]L+\epsilon[/tex] outside the range of f(x). So, I take it in this case only [tex]L-\epsilon[/tex] is considered (which made sense to me graphically since you now have two points where the function intersects this line)?

I just need verification (or correction) on this because every example and problem in the two textbooks I have has given/displayed an L and an epsilon such that [tex]L-\epsilon[/tex] and [tex]L+\epsilon[/tex] both lie within the range of f(x).

-GeoMike-

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# Homework Help: Epsilon-Delta definition of a Limit: Question

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