Eq. for displacement of current-carrying wire due to magnet

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SUMMARY

The discussion focuses on deriving the equation for the horizontal displacement of a current-carrying wire in a magnetic field, specifically the formula d = (L/mg)F. Here, L represents the distance between two vertical contacts, mg denotes the weight attached to the wire, and F is the magnetic field strength. The participants analyze the relationship between the angle theta, the displacement d, and the geometry of the setup, identifying an error in the derivation related to the presence of an extraneous factor of 4. The correct derivation involves understanding the trigonometric relationships in the free-body diagram of the wire.

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1. Homework Statement

a3vab1i.png

This is for a physics lab I am working on. A flowing current causes the wire to deflect towards the right a certain amount that varies depending on the current strength.

I need to derive the equation d=(L/mg)F
where
-- L is the distance between contact 1 and 2 both of which lie in the same vertical line.
-- mg is the weight attached at the end of the wire.
-- F is the strength of the magnetic field.
-- d is the horizontal displacement of the wire at the magnet

The magnets are located in the center of the setup and the vertical distance from contact 1 to the magnet can be approximated to be L/2

For the full lab, see http://skipper.physics.sunysb.edu/~physlab/phy134Lab5Magnetic_Force_v4.pdf

Homework Equations


Derive: d = (L/mg)F
F = 2*F_W *sin(theta)
theta = d/L/2 = 2d/L
See below for the derivations of the second two equations.

The Attempt at a Solution


MOMDYs7.png

Here is a free-body diagram of the wire at the point where a magnetic field moves it to the right. Equation (1) is for theta, the angle that F_W makes with the vertical.
fTqxDOs.png

I got the equation for theta as follows. Tan(theta) = Opposite/Adjacent. Taking theta to be the angle of the wire to the horizontal, opposite is equation to d and adjacent is taken to be L/2 so this will be the triangle formed by the top half of the wire and the magnet. Thus tan(theta)=d/L/2=2d/L

So I've gotten close but the 4 shouldn't be there. I know I have an error somewhere and likely, the 2s of the equations before should have canceled each other once I combined them.
 

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I also got the same eqn as yours. Check the questiin again
 
Bump.
 

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