Equal Input Voltages on Op-Amps

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When the inverting and non-inverting inputs of an op-amp comparator are equal, the output does not settle at an intermediate voltage but instead is influenced by hysteresis, leading to a stable high or low output. If the inverting input is higher than the non-inverting input, the output saturates to the maximum voltage. Conversely, if the inverting input is lower, the output drops to zero. The finite gain of the op-amp and the introduction of positive feedback help prevent the output from oscillating around the midpoint. Without proper feedback, the output can amplify noise, resulting in a square wave at low amplitude inputs.
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When the inverting input is higher than the non-inverting input, an op-amp voltage comparator will cause the output to saturate to the highest possible voltage. When the inverting input is lower that the non-inverting input, it outputs zero.

Question: what is the output when the inverting and non-inverting voltages are the same?
 
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Bill48 said:
When the inverting input is higher than the non-inverting input, an the op-amp voltage comparator will cause the output to saturate to the highest possible voltage. When the inverting input is lower that the non-inverting input, it outputs zero.

Question: what is the output when the inverting and non-inverting voltages are the same?

hi there

have a read here and see if it answers your questions

http://www.electronics-tutorials.ws/opamp/op-amp-comparator.html
 
Bill48 said:
When the inverting input is higher than the non-inverting input, an the op-amp voltage comparator will cause the output to saturate to the highest possible voltage. When the inverting input is lower that the non-inverting input, it outputs zero.

Question: what is the output when the inverting and non-inverting voltages are the same?
The part I have put in bold seems backwards to me.
 
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The op-amp comparator compares the two input voltages V+ and V–.
If it is true that V+ is greater than V–, then the output rises towards the positive supply voltage.
If it is false that V+ is greater than V–, then the output falls towards the negative supply voltage.

If the inputs are equal then the output should be half way between the supply rails. BUT,
the finite gain makes the comparator linear, so a small amount of positive feedback is used to create hysteresis. That makes sure the output will always be going towards a stable high or a stable low output voltage and so can never settle at an intermediate point.
 
Baluncore said:
and so can never settle at an intermediate point
IN the limit, the amp will just be amplifying the input noise. If one of your input waveforms is a very low amplitude sine wave, your output can be a square wave with a short burst of 'shash' at each zero crossing - that is if you don't use some positive (Schmitt Trigger) feedback to suppress it.
 
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