I Equality of Gravitational and Electrostatic force

AI Thread Summary
The discussion centers on the comparison between gravitational and electrostatic forces acting on electrons in atoms. Participants explore the feasibility of isolating electrons from ion cores to study these forces, highlighting that the gravitational pull from Earth is significantly weaker than the electrostatic force binding electrons to atoms. Calculations indicate a force difference of nine orders of magnitude, suggesting that Earth cannot dislodge an electron from an atom under normal conditions. Theoretical scenarios involving extreme densities, such as those found in neutron stars, are proposed but deemed unlikely to achieve the desired effects. Quantum mechanics is emphasized as a critical factor in understanding atomic behavior, challenging classical Newtonian models.
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So i was experimenting around with formulae and i thought to myself "could a planet rip a electron off a single electron system?" So i used this formula and i want to know if this is correct? . I know that gravity is magnitudes weaker than electrostatic force but if it were forced anyway would this be correct?
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I feel two points
1 How we can arrange the experiment so that only electrons no ion cores are under influence of gravity ? Free fall of atoms is the most familiar situation. I do not know how we can fix the position of the cores with no influence to electrons.
2 If we can fix the cores, forgetting about EM force, I wonder which is bigger gravity from the Earth or gravity from the ion core to the electrons ?
 
For a hydrogen atom with a radius of 37 picometers, placed near the surface of the Earth, I get the following results for the forces on the electron:

Tidal Force: 1.185x10-16 newtons
Electrostatic Force: 1.68x10-7 newtons

Even if my electrostatic force is an order of magnitude off due to being a classical calculation and not a quantum one, we're looking at a difference in force in the realm of nine orders of magnitude. A planet is absolutely not ripping an electron off of an atom unless the electron is only bound to the atom in the loosest possible sense of the word 'bound'.
 
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Drakkith said:
Tidal Force:
It's worth noting that the tidal force calculation addresses @anuttarasammyak's objection about the nucleus apparently being unaffected by gravity in the OP's calculation. This tidal force approach is the correct way to go about this, not the OP's calculation.
anuttarasammyak said:
I wonder which is bigger gravity from the Earth or gravity from the ion core to the electrons ?
Earth. Atomic masses are of order ##10^{-27}\mathrm{kg}##, electrons about three orders of magnitude lower, and atomic radii ##10^{-10}\mathrm{m}##. That gives you a gravitational force around ##10^{-48}\mathrm{N}##. Assuming Newtonian gravity is remotely valid for atoms.
 
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Drakkith said:
For a hydrogen atom with a radius of 37 picometers, placed near the surface of the Earth, I get the following results for the forces on the electron:

Tidal Force: 1.185x10-16 newtons
Electrostatic Force: 1.68x10-7 newtons

Even if my electrostatic force is an order of magnitude off due to being a classical calculation and not a quantum one, we're looking at a difference in force in the realm of nine orders of magnitude. A planet is absolutely not ripping an electron off of an atom unless the electron is only bound to the atom in the loosest possible sense of the word 'bound'.
I think you are right and this is only a theoretical possibility , i thought it could become true only if we have mass in 50s of magnitude , neglect gravitational force of proton ,and have radius not more than magnitudes of 6 or 7. Also i was using the bohrs model where radius of hydrogen atom wpuld be 0.529 angstrong
 
PhysicsEnjoyer31415 said:
I think you are right and this is only a theoretical possibility , i thought it could become true only if we have mass in 50s of magnitude , neglect gravitational force of proton ,and have radius not more than magnitudes of 6 or 7. Also i was using the bohrs model where radius of hydrogen atom wpuld be 0.529 angstrong
In order to get large tidal force, putting an atom very closed to a tiny densed mass instead of planet would be interesting.
 
anuttarasammyak said:
In order to get large tidal force, putting an atom very closed to a tiny densed mass instead of planet would be interesting.
Would definitely love to see that
 
anuttarasammyak said:
In order to get large tidal force, putting an atom very closed to a tiny densed mass instead of planet would be interesting.
I think it still might not be enough to pull a electron even if we hold down the proton somehow. That would require a huge density which i am not sure is possible or not , maybe a neutron star or something but it would surely be interesting
 
PhysicsEnjoyer31415 said:
I think you are right and this is only a theoretical possibility.
Actually, he demonstrated that it's a theoretical impossibility.
 
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PhysicsEnjoyer31415 said:
I think it still might not be enough to pull a electron even if we hold down the proton somehow. That would require a huge density which i am not sure is possible or not , maybe a neutron star or something but it would surely be interesting
There's a little thing called Quantum Mechanics that may be relevant here. You don't get far with a Newtonian model of the atom.
 
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PeroK said:
There's a little thing called Quantum Mechanics that may be relevant here. You don't get far with a Newtonian model of the atom.
Yes
 

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