1. The problem statement, all variables and given/known data Find the vector equation of a plane that contains the point P(2,-3,0) and is parallel to the yz-plane 2. Relevant equations Vector equation is in the form... Pi: r = point + t(u) + s(v) s,t element of real numbers 3. The attempt at a solution We know that the direction vectors (u and v) for a plane parallel to the yz-plane don't have x = 0 (no x component). So the simplest answer to this would be... Pi: r = P(2,-3,0) + t(0,1,0) + s(0,0,1) s,t element of R However, another possible answer would be... Pi: r = P(2,-3,0) + t(0,1,1) + s(0,1,2) s,t element of R Although the second answer is a little more complex, it defines a plane that is parallel to the yz-plane. However, my teacher insists that the plane I defined (second answer) isn't parallel to the yz-plane. Is there some way for me to prove that it is? (I am trying to explain my visualization to her but she is very insistent that my answer is wrong).