Equation of Motion for a Pendulum

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SUMMARY

The discussion focuses on the equations of motion for a simple pendulum, specifically analyzing the behavior of the pendulum bob at small angles (|theta| << 1). The key equations of motion are reduced to simpler forms for the x, y, and z components, with emphasis on the tension (T) and gravitational force (mg). The tension remains in the z component while the gravitational force is also present, as the tension approximates mg for small displacements. Dividing by mass is necessary to standardize the equations into a differential equation format.

PREREQUISITES
  • Understanding of basic physics concepts related to pendulum motion
  • Familiarity with the Small Angle Approximation
  • Knowledge of forces acting on a pendulum (tension and gravity)
  • Ability to manipulate and simplify equations in physics
NEXT STEPS
  • Study the Small Angle Approximation in detail
  • Explore the derivation of the equations of motion for a pendulum
  • Learn about differential equations in classical mechanics
  • Investigate the role of tension in various physical systems
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Students studying classical mechanics, physics educators, and anyone interested in the dynamics of pendulum motion and the application of differential equations in physical systems.

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Homework Statement



The question involves a simple pendulum, I am given three equations (1), (2) and (3) of motion for the bob at latitude (fi) for the x, y and z components.

the question then tells me to show that for small displacements meaning |theta|<< 1 (the angle between the string and the z direction in the centre of the x and y planes is very small) the three equations of motion will reduce to equations (4) (5) and (6).

my main problem is understanding how the equation in the z component reduces, especially regarding why the Tension remains as well as the force of gravity.

I also don't know the reason why we have to divide everything by mass.




Homework Equations



[PLAIN]http://img802.imageshack.us/img802/4642/equationsofmotion.jpg

The Attempt at a Solution



I understand when (theta) is very small, the Tension in the string is almost equal to (mg)
T = mg

this explains that in the x and y components the Tension becomes mg. but in the z component I don't understand why Tension stays as T, while still keeping mg in the equation.

as for mass, I am guessing mass is negligible because the tension is mg, thus mass cancels out, but still doesn't explain why the z component stays.
 
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Look up Small Angle Approximation and see if that helps.

The reason for dividing by mass is to get it into a standard differential equation forum.
 
makes sense now, thanks for the help :D
 

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