Is the time average of the tension in the string of the pendulum larger or smaller than
mg? By how much?
$$F = -mgsin\theta $$
$$T = mgcos\theta $$
The Attempt at a Solution
I'm mostly confused by what it means by time average. However from my understanding of the question the answer should be yes it is smaller than mg. Since $$T=mgcos\theta$$.
Therefore, it is smaller by a factor of cos(theta) unless the angle is 0 or pi in that case it is equal to mg. Does that make sense?