Equation of Sphere Homework: Center, Intersection & Equation

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Homework Help Overview

The problem involves determining the equation of a sphere given its center and a point it passes through, finding the intersection of the sphere with the yz plane, and analyzing a specific sphere equation to extract its center and radius.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the equation of the sphere and its intersection with the yz plane, while also analyzing a different sphere equation for its center and radius. Some participants confirm the calculations for parts a and c, while expressing uncertainty about part b.

Discussion Status

Some participants have provided confirmation on the correctness of the calculations for parts a and c. There is an ongoing exploration of how to approach part b, with suggestions to set x = 0 in the sphere's equation to find the intersection.

Contextual Notes

There is a noted lack of clarity regarding the interpretation of the intersection question in part b, which may affect the discussion's progression.

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Homework Statement


this problem has 3 parts

a- Determine an equation of the spere tha passes through th epint 6,-2,3 and has center -1,2,1
b- Determine the curve in which this sphere intersects the yz plane
c- Determine the center and radius of the sphere x^2 + y^2 + z^2 - 8x + 2y + 6z + 1 = 0


Homework Equations





The Attempt at a Solution



a - r^2 = (6+1)^2 + (-2-2)^2 + (3-1)^2 = 69
(x+1)^2 + (y-2)^2 + (z-1)^2 = 69 is this corect

b - i don't really understand what the question is asking

c - center is (4,-1,-3)
r = (-1 + (8^2 + 2^2 + 6^2)/4)^1/2 = 5 is this correct
 
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a -- looks good
c -- looks good

For b, the y-z plane is the plane x = 0. You have the equation of the sphere, so just set x = 0 in that equation.
 
sooooo...

1 + (y-2)2 + (z-1)2 = 69
 

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