1. The problem statement, all variables and given/known data Find the equation of the line tangent to y=(x²+3x)² (2x-2)³, when x=8 2. Relevant equations 3. The attempt at a solution dy/dx = 56x^6+144x^5-240x^4-320x^3+504x^2-144x......or........8x(x+3)(x+2)(7x-3)(x-1)² dy/dx (8) = 18282880 y(x) = 21249536 Equation of tangent line at x=8; y= 18282880x - 125013504 The problem is that this is a calc 1 question, 2 months in. There seems to be an odd space between the (x²+3x)² and (2x-2)³. I think the teacher might forgot to put a + or a - in the problem. What do you all think? If I use a minus, I get a perfect 5000 for y(8). Making the end equation y=2168x-12344. Am I doing something wrong?