Equation of tagent line when x is given, but not Y.

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SUMMARY

The discussion focuses on finding the equation of the tangent line for the function y=(x²+3x)²(2x-2)³ at x=8. The derivative calculated is dy/dx = 56x^6 + 144x^5 - 240x^4 - 320x^3 + 504x^2 - 144x, yielding a slope of 18282880 at x=8. The resulting tangent line equation is y = 18282880x - 125013504. A participant raises concerns about a potential typographical error in the original problem statement, suggesting a missing operator that could alter the function significantly.

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Homework Statement


Find the equation of the line tangent to y=(x²+3x)² (2x-2)³, when x=8

Homework Equations


The Attempt at a Solution


dy/dx = 56x^6+144x^5-240x^4-320x^3+504x^2-144x...or...8x(x+3)(x+2)(7x-3)(x-1)²
dy/dx (8) = 18282880
y(x) = 21249536

Equation of tangent line at x=8;
y= 18282880x - 125013504

The problem is that this is a calc 1 question, 2 months in. There seems to be an odd space between the (x²+3x)² and (2x-2)³. I think the teacher might forgot to put a + or a - in the problem. What do you all think?

If I use a minus, I get a perfect 5000 for y(8). Making the end equation
y=2168x-12344.

Am I doing something wrong?
 
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