Equation z = ct + d, z is measured in meters and t in seconds; dimensions of D?

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Homework Help Overview

The discussion revolves around the equation z = ct + d, where z is in meters and t is in seconds. Participants are exploring the dimensional analysis of the term d in relation to the other terms in the equation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to determine the dimensions of d by substituting known units for z and t. Some question the validity of combining terms with different units, while others express uncertainty about the implications of the equation.

Discussion Status

The discussion is active, with various interpretations being explored regarding the units of d. Some participants have provided insights into the necessity of consistent units in physical equations, while others are still questioning the relationship between the terms.

Contextual Notes

There is an ongoing examination of the assumption that z may not equal ct, which influences the analysis of d's dimensions. Participants are also considering the implications of unit consistency in physical equations.

William2
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Homework Statement


In the equation z = ct + d, z is measured in meters and t is measured in seconds. What are the dimensions (units) of d?

answer options are...
s/m, m/s, m, s, m*s

Homework Equations


The Attempt at a Solution



plugged in m for z, s for t, and m/s for c. solved for D and got 0.
 
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Assume that z is not equal to ct, then if you solve for d, what do you get?
 
rcgldr said:
Assume that z is not equal to ct, then if you solve for d, what do you get?

ermm...i'm guessing m?
 
Would it make sense to add two terms together that had different units? Like adding 5 meters plus 35 Amperes?
 
Can you solve for d and show the equation?

d = ?
 
All the individual terms in a physical equation have to have the same units.
 

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