Equilibrium Force: Solving for Centre of Mass | Homework Statement

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    Equilibrium Force
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Homework Help Overview

The discussion revolves around a problem related to static equilibrium and the center of mass, specifically involving a scenario with a pole and a box. Participants are exploring the implications of the statement regarding the form of the objects and how it relates to the center of gravity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the relevant equations for static equilibrium and discussing the distribution of weight between two individuals carrying an object. There is also a focus on the conditions for equilibrium, including both translational and rotational aspects.

Discussion Status

The discussion is active, with participants sharing their thoughts on the forces involved and the implications of the setup. Some guidance has been offered regarding the conditions for equilibrium, but multiple interpretations and questions remain open.

Contextual Notes

There are constraints noted regarding the vertical nature of the forces and the assumption that the pole does not rotate while being carried. Participants are also reflecting on the physical realities of carrying heavy objects in relation to the problem's assumptions.

CH Lee
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Homework Statement



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Homework Equations

The Attempt at a Solution


I'm not sure about which topic it is asked. I think it's something about the centre of mass . Because the statement " The pole and the box do not change form" . The answer is
(1 + tan Θ)/(1 - tan Θ)
 
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What are (all!) the relevant equations for static equilibrium ?

Who do you think will have to carry more in the right picture ? B or A ? Why ?

The "don't change form" remark is to reassure you the center of gravity stays in the same place in the box/pole combo.
 
BvU said:
What are (all!) the relevant equations for static equilibrium ?

Who do you think will have to carry more in the right picture ? B or A ? Why ?

The "don't change form" remark is to reassure you the center of gravity stays in the same place in the box/pole combo.

A will carry more, I think it's because he's in higher position.
And is there any special formula for static equilibrium ? I just draw a triangle and use the formula F=ma.
 
Hehe, you never had to carry something heavy down the stairs, I suppose ?

The conditions for equilibrium I hinted at in post #1 are in the first place ##\Sigma \vec F = 0## So that with your formula a = 0 ##\Rightarrow## v = constant. v = 0 remains v = 0. No translation.

But that's not enough. You also want no rotation, in other words: ##\Sigma \vec \tau = 0##.
And now the positions where the forces act come in the expressions.
 
Last edited:
CH Lee said:
A will carry more, I think it's because he's in higher position.
And is there any special formula for static equilibrium ? I just draw a triangle and use the formula F=ma.

F = ma comes into question when acceleration comes into question. Here, a = 0 and v = 0. All forces balance each other out. FA and FB act vertically upward. In which direction do you think 'W' acts?
 
The forces are vertical. That is a constraint on the answer given by the question statement. In an actual case of carrying a couch down a ramp the people doing the carrying probably would not arrange their hand-holds that way, but the problem requires it.

The pole is not rotating while it is being carried.
 

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