Equilibrium: Mass on an inclined plane held by a string, find the tension

Click For Summary
SUMMARY

The discussion focuses on calculating the tension in a string holding a mass on an inclined plane, emphasizing the importance of understanding force components. The correct approach involves using the equation T = mg sin(θ) to account for the angle of inclination. Participants are encouraged to draw free body diagrams to visualize the forces acting on the block, specifically the parallel and perpendicular components of gravitational force. This method allows for a more comprehensive understanding of similar problems without relying solely on memorized equations.

PREREQUISITES
  • Understanding of basic physics concepts, particularly forces and tension.
  • Familiarity with trigonometric functions, especially sine and cosine.
  • Ability to draw and interpret free body diagrams.
  • Knowledge of inclined plane mechanics.
NEXT STEPS
  • Study the derivation of the tension equation T = mg sin(θ) in inclined planes.
  • Learn how to construct and analyze free body diagrams for various scenarios.
  • Explore the effects of different angles on tension and force components.
  • Investigate other applications of trigonometry in physics problems involving inclined planes.
USEFUL FOR

Students and educators in physics, particularly those studying mechanics, as well as anyone interested in understanding the dynamics of forces on inclined planes.

Jujubee37
Messages
22
Reaction score
4
Homework Statement
A block of mass M = 6.2 kg is placed on a frictionless inclined plane that makes an angle of 40.4 deg with respect to the horizontal. The block is held in place by a massless string.

magnitude of normal force; 46.2700 N

Enter the magnitude of the tension T in the string.
Relevant Equations
Normally the equation I use is T=MG but in this case it doesn't work and I think it might be because of the angle.
6.2(9.8)=60.8 (incorrect)
46.2cos40.4= 35.2 (incorrect)
 
Physics news on Phys.org
Jujubee37 said:
Relevant Equations:: Normally the equation I use is T=MG but in this case it doesn't work and I think it might be because of the angle.
That angle is key! Start by drawing yourself a free body diagram of all the forces acting on that block. Hint: Pay close attention to the force components parallel to the incline surface.
 
  • Like
Likes   Reactions: SammyS
Doc Al said:
That angle is key! Start by drawing yourself a free body diagram of all the forces acting on that block. Hint: Pay close attention to the force components parallel to the incline surface.
If that is the case, would I used mg sinθ? I'm confused on what equation I should use.
 
Jujubee37 said:
If that is the case, would I used mg sinθ? I'm confused on what equation I should use.
Yes, but try to think more generally about this problem so you can solve all sorts of variations without having to memorize what equation goes where.

What are the parallel and perpendicular components of the gravitational force acting on the block? (Parallel and perpendicular to the incline surface.)
 
  • Like
Likes   Reactions: SammyS and Jujubee37
Doc Al said:
Yes, but try to think more generally about this problem so you can solve all sorts of variations without having to memorize what equation goes where.

What are the parallel and perpendicular components of the gravitational force acting on the block? (Parallel and perpendicular to the incline surface.)
Yes thank you I have another problem so I will try to work at it your way. thanks x
 

Similar threads

  • · Replies 45 ·
2
Replies
45
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K