# Equilibrium of a stiff plate on inclined planes

Homework Statement:
A thin stiff uniform rectangular plate with width L (L =AB) is lying on two inclined surface as shown in Fig. 3-1. The angle between the horizontal surface and the left inclined surface is α, and that between the horizontal surface and the right inclined surface is β. It is assumed that the plate length is sufficiently larger than L and both edges of the plate are smooth enough to neglect friction.

(1) In case of α+β = 90°, the static balance shown in Fig.3-1 is
Relevant Equations:
if three forces act on a body in equilibrium,
The sum of vectors is zero
The Vectors cross or intersect at same point and they are in the same plane. I HAVE NO IDEA HOW TO START.ONLY THINGS I KNOW ARE WHAT I RERAD ON THIS THRED.

I cant continue from there. There are also questions where α=β, α+β=45 and where α=45,β=60.How to make use of the fact that G will follow the arc of a circle centered at O, and that at equilibrium it is vertically above O.

haruspex
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Homework Statement:: A thin stiff uniform rectangular plate with width L (L =AB) is lying on two inclined surface as shown in Fig. 3-1. The angle between the horizontal surface and the left inclined surface is α, and that between the horizontal surface and the right inclined surface is β. It is assumed that the plate length is sufficiently larger than L and both edges of the plate are smooth enough to neglect friction.

(1) In case of α+β = 90°, the static balance shown in Fig.3-1 is
Relevant Equations:: if three forces act on a body in equilibrium,
The sum of vectors is zero
The Vectors cross or intersect at same point and they are in the same plane.

View attachment 285680

I HAVE NO IDEA HOW TO START.ONLY THINGS I KNOW ARE WHAT I RERAD ON THIS THRED.

I cant continue from there. There are also questions where α=β, α+β=45 and where α=45,β=60.How to make use of the fact that G will follow the arc of a circle centered at O, and that at equilibrium it is vertically above O.
A good start would be to draw a new diagram making use of what you gleaned from the other thread.

isn't the diagram a rectangle which has L as diagonal.
WHAT I DONOT KNOW IS How to make use of the fact that G will follow the arc of a circle centered at O AND HOW TO GET α AND β ONTO THE DIAGRAM(INTO THE GAME)

IN THE CASE OF α=45,β=60 Those don't EVEN add to 90.(DON'T THEY HAVE TO)
BUT THE QUESTION SAYS THAT STATIC BALANCE IS POSSIBLE.
HOW IS THAT.

help.

haruspex
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2020 Award
isn't the diagram a rectangle which has L as diagonal.
WHAT I DONOT KNOW IS How to make use of the fact that G will follow the arc of a circle centered at O AND HOW TO GET α AND β ONTO THE DIAGRAM(INTO THE GAME)
A diagram showing
that at equilibrium G is vertically above O.
Once you have that, all you need is geometry.
IN THE CASE OF α=45,β=60 Those don't EVEN add to 90.(DON'T THEY HAVE TO)
BUT THE QUESTION SAYS THAT STATIC BALANCE IS POSSIBLE.
HOW IS THAT.
The angles adding to 90 just makes the solution simpler. In the general case, equilibrium is still possible but I don't see any nice geometric solution.
If the distances of A and B from O are x and y, and the plate makes angle theta to the horizontal, what two equations can you write to relate them?
In terms of x, y and the given angles, what is the height of G?

DO YOU MEAN BETWEEN X,Y,THETA
IN THE GENERAL CASE OR WHEN The angles adding to 90.

I TRIED AND GOT X2+Y2= L2 WHEN The angles adding to 90.
NA cosα+NB cosβ=W
And I took a moment at point A,B
NA*X = W*L/2*cosθ
NB*Y = W*L/2*cosθ
I really can't find ANYTHING ELSE.

Last edited:

haruspex
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I TRIED AND GOT X2+Y2= L2 WHEN The angles adding to 90.
NA cosα+NB cosβ=W
And I took a moment at point A,B
NA*X = W*L/2*cosθ
NB*Y = W*L/2*cosθ
I really can't find ANYTHING ELSE.
As I wrote, you only need geometry for this case, so don't worry about forces and moments.
Have you drawn a diagram showing the angle as 90 and with G vertically above O?
What is the height of G above O? If it is not immediately obvious, complete the rectangle from the points AOB and note its diagonals.
What is the angle GOB? So what is angle GBO?
Write angle GBO in terms of beta and theta.

For the general case, consider the horizontal distance from A to B. Write it in terms of L and theta, then again in terms of x, y, alpha and beta. That gives you an equation.
Do something similar for the vertical direction.
A third equation expresses the height of G in terms of the heights of A and B.

the height of G above O=L/2
GOB=90-β
GBO=90-β+θ
LCOSθ=XCOSα+YCOSβ
LSINθ=XSINα+YSINβ
A third equation expresses the height of G in terms of the heights of A and B.(I DONOT KNOW HOW TO GET)

haruspex
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the height of G above O=L/2
GOB=90-β
GBO=90-β+θ
LCOSθ=XCOSα+YCOSβ
LSINθ=XSINα+YSINβ
A third equation expresses the height of G in terms of the heights of A and B.(I DONOT KNOW HOW TO GET)
You are mixing up the two sets of advice I gave.

The first is just for the 90 degree case. Having found the height of G above O is L/2:
What is the angle GOB? So what is angle GBO?
Write angle GBO in terms of beta and theta.

When you've finished that case, proceed to the general one. Yes
LCOSθ=XCOSα+YCOSβ
But not:
LSINθ=XSINα+YSINβ
For G in terms of the heights of A and B, remember that G is halfway between them.

L/2=X/2SINα+YSINβ
GBO=β+θ=GOB(I HOPE)

HOW TO MAKE USE OF THESE.

haruspex
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GBO=β+θ=GOB
Yes, but what is the direct relationship between GOB and β?
L/2=X/2SINα+YSINβ
No. You seem to be guessing.
Let's say B is lower than A.
What is the height of A above B in terms of:
1. x, y, α, β
2. L, θ
?

direct relationship between GOB and β MEANING.
i really do not know HOW TO GET WHAT YOU ARE ASKING

LSINθ=XSINα-YSINβ

Delta2
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@haruspex just one question, are you trying to do this via the principle of virtual work?

haruspex
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direct relationship between GOB and β MEANING.
i really do not know HOW TO GET WHAT YOU ARE ASKING
Have you drawn a diagram showing AOB as a right angle and G vertically above O?
What angle does OG make to the horizontal?
What angle does OB make to the horizontal?
So what angle does OB make to OG?

What angle does OG make to the horizontal?90
What angle does OB make to the horizontal?β
So what angle does OB make to OG?90-β

haruspex
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What angle does OG make to the horizontal?90
What angle does OB make to the horizontal?β
So what angle does OB make to OG?90-β
Sorry, just realised you already got that in post 11.
GOB=90-β
Combine that with your equation in post 13:
β+θ=GOB

2β+θ=90

haruspex
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2β+θ=90
So now you have the value of theta for the right angle case.

On to the general case?

On the general case WHAT TO DO?

haruspex