Equipotential surface

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SUMMARY

The discussion centers on calculating the radius of an equipotential surface for a point charge of +3.50 microC at a potential of 2.40 kV. The formula used is voltage = kq/r, where k is 9 x 10^9 N*m^2/C^2. The calculated radius is 13.1 m, while the expected answer is 12.6 m. The discrepancy is attributed to the approximation of the constant k.

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"For a point charge of +3.50 microC what is the radius of the equipotential surface that is at a potential of 2.40 kV?"

For a point charge, the voltage = kq/r, where k =9*10^9 N*m^2/C^2, q is the charge, and r is the radius. Solving for r, I get r = 13.1 m. But the answer is 12.6m...
 
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Your method is correct.
The difference isn't all that alarming and has probably risen in your approximate value of k .
 
ok, thanks!
 

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