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Equipotential Surfaces and Electric Field

  1. Mar 13, 2010 #1
    1. The problem statement, all variables and given/known data

    A given system has the equipotential surfaces shown in the figure .
    http://session.masteringphysics.com/problemAsset/1122530/1/Walker.20.39.jpg

    A)What is the magnitude of the electric field?
    B)What is the direction of the electric field? (in degrees from the +x axis)
    C)What is the shortest distance one can move to undergo a change in potential of 1.50 V?


    2. Relevant equations
    E=-V/R


    3. The attempt at a solution
    I found the answer to the Part A:
    E= -V/R, R=4sin(26.565)
    E=559 V/M

    I cannot wrap my head around the answer to Part B, though. I thought it would simply be 180-25.65, but that's wrong. Any help?

    I also know how to do Part C, so just Part B would be great!
     
  2. jcsd
  3. Mar 14, 2010 #2
    Answers that are also not correct are:
    153
    63.4
    117.
     
  4. Mar 14, 2010 #3
    Nevermind, I was doing the angle perpendicular in the wrong direction. I got the answer.
     
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