- #1

predentalgirl1

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**[SOLVED] Equipotential Surfaces Question**

**If the radius of the equipotential surface of point charge is 14.3 m at a potential of 2.20 kV, what is the magnitude of the point charge creating the potential?**

**have V = [1/4πεo] [q/r]**

Given that,

V = 2.20kV = 2200V

r = 14.3m

Therefore,

q = 2200 x 14.3

9.0 x 10^9

= 3.495 x 10-6μC

Given that,

V = 2.20kV = 2200V

r = 14.3m

Therefore,

q = 2200 x 14.3

9.0 x 10^9

= 3.495 x 10-6μC

Correct? Not correct? Please help me!