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## Homework Statement

What is the equivalent capacitance for the following schematic?

Note that C1 is 11 µF, and C2 is 3 µF.

http://img511.imageshack.us/img511/8051/questionzi5.png [Broken]

## Homework Equations

[tex]C_{parallel} = C_1 + C_2 + C_3 + ... + C_n[/tex]

[tex]\frac{1}{C_{series}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + ... + \frac{1}{C_n}[/tex]

## The Attempt at a Solution

I tried the following:

1: Considered the four right-hand caps to be in parallel and add them as above, yielding 47 µF, and:

2: Added that 47 µF cap in series with the remaining 5 µF and 3 µF caps like so:

[tex]C_{eq} = \frac{1}{\frac{1}{5} + \frac{1}{47} + \frac{1}{3}} = 1.8051 \mu F[/tex]

But no go (and appropriately so, since the number seems a bit small). Where am I making a mistake?

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