What is the Effective Capacitance Across A and B in This Network?

[Suraj M]

Homework Statement

Here's the question as it was given.

we should find the effective capacitance across A and B,

Homework Equations

$C_p = C_1 +C_2+...$
$\frac{1}{C_s} = \frac{1}{C_1} +\frac{1}{C_2} +...$

The Attempt at a Solution

Looking at the diagram i thought The capacitance should be zero.. shouldn't it be zero?
because there is a wire directly connecting A and B.
but the answer was given as 132 µF, that would happen if the 4 capacitors were in parallel, like this maybe

then yes it should be 132µF.
i still think that the answer to the original question is zero, could someone verify or correct me.
Thank you

 

[NascentOxygen]

Your first circuit is a short circuit so has no capacitance. The second one is 123uF.

 

[Suraj M]

one is 123uF.

You mean 132 µF
Thank you, just needed to be sure.:)