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Introductory Physics Homework Help
Error calculation for moment of inertia
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[QUOTE="lydiazmi, post: 3210717, member: 315252"] [h2]Homework Statement [/h2] I did an experiment, n now I hv to calculate the error. [h2]Homework Equations[/h2] This equation is given: mR^2((gt^2/2h)-1) [h2]The Attempt at a Solution[/h2] I found out that t=1.658s delta t=0.094s h=0.31m delta h=0.5*10^-3m m=0.5456kg delta m=0.5*10^-4kg R=5.4*10^-3m delta R=5.1*10^-4m g=9.806m/c^2 delta g=0.006m/c^2 d I= square root of ((delta m/m)^2+4(delta R/R)^2+(delta g*t^2/(gt^2-2h))^2+4(delta t*gt/(gt^2-2h))^2+(delta h*gt^2/(ght^2-2h^2)^2) and I got 0.22 which means 22%. For error, I suppose this is too much. Why? [/QUOTE]
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Introductory Physics Homework Help
Error calculation for moment of inertia
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