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## Homework Statement

I did an experiment, n now I hv to calculate the error.

## Homework Equations

This equation is given: mR^2((gt^2/2h)-1)

## The Attempt at a Solution

I found out that

t=1.658s

delta t=0.094s

h=0.31m

delta h=0.5*10^-3m

m=0.5456kg

delta m=0.5*10^-4kg

R=5.4*10^-3m

delta R=5.1*10^-4m

g=9.806m/c^2

delta g=0.006m/c^2

d I= square root of ((delta m/m)^2+4(delta R/R)^2+(delta g*t^2/(gt^2-2h))^2+4(delta t*gt/(gt^2-2h))^2+(delta h*gt^2/(ght^2-2h^2)^2)

and I got 0.22 which means 22%. For error, I suppose this is too much. Why?