Error calculation for moment of inertia

  • Thread starter lydiazmi
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Homework Statement


I did an experiment, n now I hv to calculate the error.

Homework Equations


This equation is given: mR^2((gt^2/2h)-1)


The Attempt at a Solution


I found out that

t=1.658s
delta t=0.094s
h=0.31m
delta h=0.5*10^-3m
m=0.5456kg
delta m=0.5*10^-4kg
R=5.4*10^-3m
delta R=5.1*10^-4m
g=9.806m/c^2
delta g=0.006m/c^2

d I= square root of ((delta m/m)^2+4(delta R/R)^2+(delta g*t^2/(gt^2-2h))^2+4(delta t*gt/(gt^2-2h))^2+(delta h*gt^2/(ght^2-2h^2)^2)

and I got 0.22 which means 22%. For error, I suppose this is too much. Why?
 

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