I'm trying to work out the percentage error in working out the value of gravity,g, from a pendulums motion. i know that percentage error is (possible error/value used)*100 however im using multiple values multiple times and its getting a little confusing. In the investigation g=k(∆T²/∆L), my problem is that i have the error for working out T which is 0.001 seconds. The error in L is 0.001m. As i'm using a difference of two values for each of the ∆'s would i double each error and for the error of T² would i square 0.001 and then double it. any explainations would be helpful Thanks ∆T²=2.112 ∆L=0.51
You know that [tex]T=2\pi \sqrt{\frac{l}{g}}[/tex] so that [tex]T^2=4\pi^2 \frac{L}{g}[/tex] and that means that [tex]g=\frac{4\pi^2}{T^2}L[/tex] To find the error you do this. [tex]\frac{\delta g}{g}=2\frac{\delta T}{T} + \frac{\delta L}{L}[/tex] [itex]\delta T[/itex] would be the error in T and similarly for [itex]\delta L[/itex] is the error in L.