Error in asnwer? Finding the transfer function of a system

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SUMMARY

The discussion centers on finding the transfer function and impulse response for the system defined by the differential equation y'(t) + y(t) = x(t), with the input x(t) being a piecewise function. The correct transfer function is established as H(s) = 1/(s+1) after transforming the equation into the Laplace domain. A critical point raised is the initial condition y(0) = 1, which complicates the calculation of H(s) = Y(s)/X(s). The input function x(t) is clarified as x(t) = H(t) - H(t - 1), where H is the Heaviside function, leading to X(s) = 1 - e^{-s}.

PREREQUISITES
  • Understanding of Laplace transforms and their properties
  • Familiarity with differential equations and their solutions
  • Knowledge of the Heaviside step function
  • Experience with transfer functions in control systems
NEXT STEPS
  • Study Laplace transform techniques for solving linear differential equations
  • Learn about the Heaviside function and its applications in signal processing
  • Explore the derivation of transfer functions from state-space representations
  • Investigate impulse response calculations and their significance in system analysis
USEFUL FOR

Students and professionals in engineering, particularly those focusing on control systems, signal processing, and differential equations, will benefit from this discussion.

toofle
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Homework Statement


Find the transfer function and the impulse response for the system:

y'(t) + y(t) = x(t)

x = {1 if 0<=t<1,0 1<=t}



Homework Equations



d/dt y(t) ~ sY(s) -y(0)


The Attempt at a Solution



I transform into the laplace-domain:
sY(s) - y(0) + Y(s) = X(s)
Y(s)(s+1) - 1 = X(s)

Here I can't get H(s)=Y(s)/X(s) beacuse of y(0)=1 and not 0.

The answer is H(s) = 1/(s+1) . then it is easy to get the impulse response by backtransforming to the timedomain so that's no problem.
But there must be an error in the answer or problem statement right?
 
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toofle said:

Homework Statement


Find the transfer function and the impulse response for the system:

y'(t) + y(t) = x(t)

x = {1 if 0<=t<1,0 1<=t}



Homework Equations



d/dt y(t) ~ sY(s) -y(0)


The Attempt at a Solution



I transform into the laplace-domain:
sY(s) - y(0) + Y(s) = X(s)
You have a mistake on the right side, in that you have not put in the function given as x(t).

x(t) = H(t) - H(t - 1), where H is the Heaviside function.

So [itex]X(s) = \mathcal{L}(x(t)) = e^{-0} - e^{-s} = 1 - e^{-s}[/itex]
toofle said:
Y(s)(s+1) - 1 = X(s)
Now, substitute for X(s) above, and see how it come out.
toofle said:
Here I can't get H(s)=Y(s)/X(s) beacuse of y(0)=1 and not 0.

The answer is H(s) = 1/(s+1) . then it is easy to get the impulse response by backtransforming to the timedomain so that's no problem.
But there must be an error in the answer or problem statement right?
 

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