Error propagation of q=mcdeltat

Click For Summary
Error propagation for the equation cNi= [-(mcΔt)Al-(mcΔt)H2O]/(mΔt)Ni can be approached using the partial derivative method, which simplifies calculations involving multiple variables. The uncertainty in the result is calculated using the formula Δf = √[(∂f/∂x)²Δx² + (∂f/∂y)²Δy² + (∂f/∂z)²Δz²], allowing for accurate propagation of errors from mass and temperature. The discussion highlights that uncertainties for both mass and temperature are approximately 0.1, but the user is unsure which values to substitute into the error propagation equation. This method is recommended for its effectiveness in handling complex functions without breaking them down into simpler components. Utilizing this approach will help clarify the error propagation process in the given scenario.
Duderonimous
Messages
63
Reaction score
1

Homework Statement


I want to know how to do error propagation on this

cNi= [-(mcΔt)Al-(mcΔt)H2O]/(mΔt)Ni

m is mass and Δt is change in temperature

Homework Equations



δc/c=√(δm/m)2+(δ(Δt)/Δt)2

The Attempt at a Solution



I know the above error prop eq. above applies to c=Q/mΔt
or I think it does.

But I just can't figure it out. The uncertainty for both is about 0.1. I have about 3 different values mass and 2 different values for temperature. What values do I substitute into the error prop equation. Any help would be great. Doing it last minute and its becoming a nightmare.
 
Physics news on Phys.org
When you're looking to propagate the errors when the solution is a non-trivial function of several variables, I'd suggest using the partial derivative method. This avoids breaking the function down into elementary additions, multiplications, powers, etc., and slogging through the error math for each one of them.

If you have a function of, say, three variables f(x,y,z), and associated uncertainties Δx, Δy, Δz, for the variables, then the uncertainty in the result of a calculation of f(x,y,z) is given by:

$$Δf = \sqrt{\left(\frac{\partial f}{\partial x}\right)^2 Δx^2 + \left(\frac{\partial f}{\partial y}\right)^2 Δy^2 + \left(\frac{\partial f}{\partial z}\right)^2 Δz^2} $$

This is easy to remember, applies to function of any number of variables, and best of all it always works, even if the function f contains other functions like sin(x) or ln(x) or,...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
25
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K