Essentials of Calculus use a calculator to estimate any extrema

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To estimate the extrema of the function f(x)=5x^3-30x^2+45x+5(sqrt(x)), graphing the function or its derivative f'(x)=15x^2-60x+45+(5/2)x^(-1/2) using a calculator is recommended. Observing where the graph of f'(x) crosses the x-axis can indicate critical points. For a simpler estimation, graphing f(x) directly allows identification of local maxima and minima. Numerical methods like Newton's method can also be utilized for more precise calculations. Estimating extrema can be effectively achieved through graphical analysis.
Nawz
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Homework Statement




Use a calculator to estimate any extrema of this function:
f(x)=5x^3-30x^2+45x+5(sqrt(x))

Homework Equations





The Attempt at a Solution



I don't know how to find it using a calculator.

f'(x)= 15x^2-60x+45+(5/2)x^(-1/2)
 
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If your calculator is a graphing calculator, graph y= f'(x) and see where it crosses the x- axis. Another method of solving such an equation is to use a "Newton's method" or some other numerical method.
 
Nawz said:

Homework Statement




Use a calculator to estimate any extrema of this function:
f(x)=5x^3-30x^2+45x+5(sqrt(x))

Homework Equations





The Attempt at a Solution



I don't know how to find it using a calculator.

f'(x)= 15x^2-60x+45+(5/2)x^(-1/2)

Since you are estimating, you can simply graph f(x) and look for peaks (maxes), troughs (mins), and where the graph changes concavity (inflection points; though most books do not consider this an extremum). The derivative is not really needed, unless you want a more accurate estimate.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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