Estimate the velocity and angular velocity of an empty pipe

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SUMMARY

The discussion focuses on estimating the velocity and angular velocity of an empty pipe with a mass of 1000 kg, a diameter of 10 mm, and a shell thickness of 1 mm, positioned on a slope of 45 degrees with a path length of 5000 mm on Uranus, where gravitational acceleration is 8.9 m/s². Key insights include using energy balance principles, where potential energy (PE) is converted into kinetic energy (KE), and considering moment of inertia (MoI) losses due to the shell thickness. The final velocity can be derived from the energy equations, and angular velocity can be calculated from the diameter once the final velocity is known.

PREREQUISITES
  • Understanding of energy conservation principles in physics
  • Familiarity with potential energy (PE) and kinetic energy (KE) equations
  • Knowledge of moment of inertia (MoI) and its impact on rotational motion
  • Basic trigonometry for calculating height from slope angle
NEXT STEPS
  • Study energy balance in mechanical systems
  • Learn about moment of inertia calculations for different shapes
  • Explore the relationship between linear velocity and angular velocity
  • Investigate gravitational effects on different planetary bodies
USEFUL FOR

Students preparing for physics exams, engineers working on dynamics problems, and anyone interested in the mechanics of motion on different planetary surfaces.

Calum Mulryan
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Hi, I need to resit some exams and I'v been having difficulty trying to solve this problem.

Estimate the velocity and angular velocity of an empty pipe of mass (m)=1000kg, Diameter (d)=10mm, shell thickness (h)=1mm at the bottom of a slope of angle [tex]\theta[/tex]=45[tex]^{}o[/tex] and path length L=5000mm on the planet uranus (g=8.9 m/s[tex]^{}-2[/tex])

thanks

Calum
 
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firstly, i have no interest in doing the problem for you (don't think you'll learn - i had to learn that the hard way); however, i have a high interest that you do well in your exam.

perhaps this may help:

use an energy balance: all potential energy is converted into kinetic energy

use trig knowing the hypotenuse is 5000m, and theta is 45*. easy to find the height.
you know the mass, and g. PE=mgh

shell thickness is to account for moment of inertia losses. unfortunately I am at a loss (in the 1 minute while i type this, and i don't have a dynamics book at my desk). something like I*(ang vel)^2, though

that equals 1/2 m Vfinal^2

so we have PE - MoI losses = KE
the MoI losses will act like a friction loss for the most part where they are summed along the length of the path (i.e. retarding force* distance it acts along)

from Vfinal, knowing diameter, you can find omega without too much difficulty

sorry i can't help too much on the MoI stuff, my book is 60 miles away. perhaps tomorrow if you are still stuck, i'll come back. or another member can contribute

or tell your professor that Uranus is gaseous, and therefore has no surface in which to support the ramp, so for practical purposes the problem does not require a solution
 

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