# Estimate the velocity of each stone have just after the collision

Hi I really need a answer to this task. Hope anyone can help.

A curling stone ( named A ) gets on the ice with a unknown beginning velocity Vo
the stone moves along a straight line ( x axis ) on the x axis further ahead lies another
stone ( named B ) still. Stone A collides with stone B in a sloped hit/knock
Just before the hit stone A has a velocity of 2m/s. After the slope stone A moves
straight with a angle of 45 degree in proportion at/of the x axis. Equivalently for stone B is -30 degrees.

a ) Estimate the velocity of each stone have just after the collision

b) Estimate the loss of kinetic energy in this collision. A curling stone have mass 20kg. what kind of collision is this ?

The reason for the energy loss is that big is that ice-sludge came between the stones in the collision. We clean up and retake the attempt. Now we reckon that the push is approximate perfect elastic Stone A has the velocity of 2 m/s before the push/hit and 1,5m/s after. The direction of a form the angle 41,3 degree with the x axis after the push/hit.

c) Find the velocity and direction of B after the stone is Pushed/released.

d ) Check that the push of the stone is approximated elastic, by calculate the x component

Related Introductory Physics Homework Help News on Phys.org
a) use conservation of momentum in the x and in the y direction.

Thanks. But can I get some moore information Im a noob :)

none ?

Hootenanny
Staff Emeritus
Gold Member
Thanks. But can I get some moore information Im a noob :)
What further information do your require?

What further information do your require?
The formula and correct answer would been nice

Hootenanny
Staff Emeritus
Gold Member
The formula and correct answer would been nice
Nope, we don't do that here. Your going to have to do some work yourself. What can you say about the total momentum before and after the collision?

Nope, we don't do that here. Your going to have to do some work yourself. What can you say about the total momentum before and after the collision?
Its less after the collition (velocity) ? Not sure what mometum means movement/direction or velocity ? But im guessing its velocity
Im Not english

Hootenanny
Staff Emeritus