Estimating Avogadro's Number Using Surface Tension Experiment

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SUMMARY

The forum discussion focuses on estimating Avogadro's number using a surface tension experiment with n-butanol in water, employing the capillary rise method. The user calculated the number of moles adsorbed at the surface per unit area as n/A = 5.012 x 10-3 mol⋅cm-2 and determined the capillary radius to be r = 0.0386273 cm. Despite following the Gibb's adsorption equation and relevant volume calculations, the user arrived at an incorrect estimate of Avogadro's number, NA = 949 molecules/mol, indicating a significant error in their methodology.

PREREQUISITES
  • Understanding of Gibb's adsorption equation
  • Familiarity with capillary rise method in surface tension experiments
  • Knowledge of volumetric calculations for molecular dimensions
  • Basic principles of mole and Avogadro's number
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  • Review the Gibb's adsorption equation and its application in surface tension experiments
  • Learn about the capillary rise method and its implications for measuring surface tension
  • Study volumetric calculations for cubic molecules and their relevance in molecular physics
  • Investigate common errors in estimating Avogadro's number and how to avoid them
USEFUL FOR

Students and researchers in chemistry, particularly those involved in physical chemistry experiments, surface science, and molecular calculations, will benefit from this discussion.

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Homework Statement



I did a surface tension experiment with n-butanol in water using the capillary rise method. Using my data and the Gibb's adsorption equation, I found the number of moles adsorbed at the surface per unit area to be
n/A = 5.012 x 10-3 mol⋅cm-2.

I also calculated the radius of the capillary to be r = 0.0386273 cm.

Given that the density of n-butanol is assumed to be the same as water ρ = 0.9970 g⋅cm-3
and the molar volume of n-butanol is Vm = 91.5 cm3⋅mol-1, estimate Avogadro's number.

Also assume the surface is a monolayer of n-butanol molecules, and that an n-butanol molecule is a cube.

Homework Equations



Vmolecule = Vcube = h3

Vmonolayer = Vcylinder = πr2h

h = Vm/(n/A)

# of molecules = Vmonolayer/Vmolecule

n = (n/A)πr2

NA = Avogadro's number = # of molecules/n

The Attempt at a Solution



Since the surface is a monolayer, I think the length of a molecule is the height of the monolayer.
h = 91.5cm3⋅mol-1/5.012 x 10-3 mol⋅cm-2 = 0.459 cm

Now I can calculate the volume of a single cubic molecule to be:
Vmolecule = h3 = (0.459 cm)3 = 0.0964 cm3

and the volume of the monolayer is:
Vmonolayer = π(0.0386273 cm)2(0.459 cm) = 2.15 x 10-3 cm3

(This must already be incorrect since the volume of a single molecule can't be larger than that of the whole monolayer of molecules).

The number of molecules would incorrectly be:
# of molecules = (2.15 x 10-3 cm3)/(0.0964 cm3) = 0.0223 molecules

The number of moles is:
n = (5.012 x 10-3 mol⋅cm-2)(0.0386273 cm)2π = 2.349 x 10-5 mol

Then Avogadro's number is calculated as:
NA = (0.0223 molecules)/(2.349 x 10-5 mol) = 949 molecules/mol

..which is unbelievably wrong. Any help is appreciated!
 
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JM92 said:
Since the surface is a monolayer, I think the length of a molecule is the height of the monolayer.
h = 91.5cm3⋅mol-1/5.012 x 10-3 mol⋅cm-2 = 0.459 cm

0.459 cm per molecule already should tell you something is terribly wrong at this stage.
 
Borek said:
0.459 cm per molecule already should tell you something is terribly wrong at this stage.
Right, didn't notice that. Do you have any suggestions on how I could properly start this then? Thank you!
 
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