Estimating f(2) using Cubic Interpolation

Click For Summary
SUMMARY

The discussion focuses on estimating the value of f(2) using cubic interpolation based on the known function values f(0) = -32, f(1) = 0, f(3) = 10, and f(4) = 0. The correct estimated value is 12. Participants discuss the transition from quadratic and linear interpolation to cubic interpolation, specifically referencing the Lagrange interpolating polynomial and the formulation of the cubic polynomial g(x) = a + bx + cx² + dx³. The method involves solving for the constants using the provided function values.

PREREQUISITES
  • Cubic interpolation techniques
  • Lagrange interpolating polynomial
  • Polynomial function formulation
  • Basic understanding of function evaluation
NEXT STEPS
  • Study the derivation of the Lagrange interpolating polynomial
  • Learn how to solve for coefficients in polynomial functions
  • Explore numerical methods for interpolation
  • Investigate applications of cubic interpolation in data fitting
USEFUL FOR

Mathematicians, data analysts, and students studying numerical methods who need to understand cubic interpolation and its applications in estimating function values.

escobar147
Messages
31
Reaction score
0
If a cubic function satisfies f(0) = -32, f(1) = 0, f(3) = 10 and f(4) = 0,
use cubic interpolation to estimate f(2)



I'm not sure how to approach this since I have only ever done quadratic interpolation and linear interpolation, is it just an extension of the lagrange interpolating polynomial?

If so could someone please show me what form to put it in?

The correct answer is 12, however my attempt at extending lagrange give me nowhere near that?!

any help would be hugely appreciated!
 
Physics news on Phys.org
could you just start with g(x) = a+bx+cx^2+dx^3 and solve for the constants given the points you have?
 
There are many ways one of which being
P(x)=\sum_{i=1}^n \frac{\pi(x)}{\pi\prime(x_k)}\frac{f(x_i)}{x-x_i}
where in this case n=4 and
π(x)=(x-0)(x-1)(x-3)(x-4)
x1=0;x2=1;x3=3;x4=4
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K