Estimation of the volume of a solid.

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SUMMARY

The discussion focuses on estimating the volume of a solid with a base defined by the curves y = x + 3 and y = x² - 3, and bounded above by the surface z = x² + y. The intersection points of the base curves are identified at x = -2 (y = 1) and x = 3 (y = 6). The volume is calculated using rectangular cross-sections perpendicular to the x-axis, leading to the formulation of the area as the difference in y-values, resulting in the expression -x² + x + 6 for the base area. The integration of this area from x = -2 to x = 3 is necessary to find the total volume.

PREREQUISITES
  • Understanding of Calculus, specifically integration techniques
  • Familiarity with functions and their intersections
  • Knowledge of rectangular cross-sections in volume estimation
  • Ability to manipulate algebraic expressions and equations
NEXT STEPS
  • Study the method of calculating volumes using integration in Calculus
  • Learn about finding intersections of curves and their significance in volume problems
  • Explore the concept of cross-sections and their applications in solid geometry
  • Practice problems involving volume estimation of solids with varying boundaries
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Students studying Calculus, particularly those focusing on volume estimation techniques, as well as educators seeking to enhance their teaching methods in solid geometry.

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Homework Statement


Estimate the volume of the solid whose base is bounded by the graphs of y = x + 3 and
y = x2 − 3, and bounded by the surface z=x2+y from above, using the indicated rectangular cross sections taken perpendicular to the x-axis (figure is not the actual graph of the functions given above. It is solely a demonstration to help with the problem).


Homework Equations





The Attempt at a Solution



I've been trying to figure out a way to solve it for hours.
The only thing that I've done was figure out the area of the base, but i don't know if I am on the right track or not, seeing as the professor has not gone over this.
 
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Did the problem really say "estimate"? It's a pretty straight forward Calculus problem to find the exact volume.
The base graphs y= x+ 3 and y= x^2- 3 (note that "x^2" is clearer than "x2") intersect where y= x+ 3= x^2-3 or x^2- x- 6= (x- 3)(x+ 2) or x= -2, y= 1 and x= 3, y= 6. Rectangular cross-sections perpendicular to the x-axis" means that the area is "height times base" where the base is the difference in y values, x+3-(x^2- 3)= -x^2+ x+ 6 and the height is z= x^2+ y. The volume of a thin "slab" would be that area multiplied by thickness, dx. Integrate that from x= -2 to 3.
 
So then would the actual area end up being:
-x^4+x^3+6x^2-x^2y+xy+6y
Or am i wrong?

If it is right,would the volume be (125/12)*(2y+3)
 

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