Evaluate the Limit (just confirmation)

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Homework Help Overview

The discussion revolves around evaluating the limit of the expression (cubicsquareroot(x) - 2)/(x-8) as x approaches 8. The subject area involves limits and potentially the application of L'Hôpital's rule in calculus.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the original limit expression and the indeterminate form it presents. Some mention changing variables and using substitutions to simplify the limit. There is also a discussion about the terminology used, specifically the term "cubicsquareroot."

Discussion Status

Some participants have confirmed the correctness of the original poster's approach, while others suggest that additional substitutions could enhance clarity. There is an acknowledgment of the potential application of L'Hôpital's rule, although some believe it is unnecessary for this problem.

Contextual Notes

There is a mention of the original problem being revised to a different form involving a limit as p approaches 2, which indicates a shift in the approach being discussed. The conversation also highlights some confusion regarding terminology and assumptions about the function involved.

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Homework Statement



lim (cubicsquareroot(x) - 2)/(x-8)
x→8



Homework Equations





The Attempt at a Solution



I obtained 1/12 as my final answer, after changing the variable since its in indeterminate form.
..let p=cubicsquareroot(x), then as x→8, p→2
then, p^3=x

Using this logic I obtained 1/12.

Is this correct ?
 
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NATURE.M said:

Homework Statement



lim (cubicsquareroot(x) - 2)/(x-8)
x→8



Homework Equations





The Attempt at a Solution



I obtained 1/12 as my final answer, after changing the variable since its in indeterminate form.
..let p=cubicsquareroot(x), then as x→8, p→2
then, p^3=x

Using this logic I obtained 1/12.

Is this correct ?

Precisely, Although It'd be nicer if you had done some substitutions.. Yeah is correct!
 
PrashntS said:
Precisely, Although It'd be nicer if you had done some substitutions.. Yeah is correct!

My bad! you have! And when you reach L'Hopital's rule, revisit these questions..
 
What's a "cubicsquareroot" ?
 
SammyS said:
What's a "cubicsquareroot" ?

Assumed he meant x^(1/3) *kids today*
 
lol Yeah I mean't x^(1/3). And thanks.
 
PrashntS said:
My bad! you have! And when you reach L'Hopital's rule, revisit these questions..
L' Hopital's Rule is not needed in this problem.

The OP apparently revised the original problem to this form:
$$ \lim_{p \to 2} \frac{p - 2}{p^3 - 8}$$

and then factored the denominator to (p - 2)(p2 + 2p + 4), and then took the limit.
 

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