Evaluating a Surface Integral: A Parallelogram

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Homework Help Overview

The discussion revolves around evaluating a surface integral defined over a parallelogram with specific parametric equations. The function to be integrated is f(x,y,z) = x + y + z, and the parameters u and v are constrained within given limits.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty about how to begin tackling the surface integral. Some suggest reviewing relevant material on surface integrals. There are attempts to formulate the integral using the appropriate mathematical expressions, and discussions arise regarding the calculation of the determinant and its magnitude.

Discussion Status

There is an ongoing exploration of the correct approach to the problem, with some participants providing guidance on the formulation of the integral. Discrepancies in the calculation of the determinant's magnitude have been noted, indicating a divergence in understanding that is still being addressed.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can share or the methods they can use. There is an emphasis on clarifying definitions and ensuring accurate calculations throughout the discussion.

bugatti79
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Homework Statement



Evlute the surface integral

Homework Equations



f(x,y,z)=x+y+z where sigma is the parallelogram with parametric equations x=u+v, y=u-v and z=1+2u+v where 0 <=u<=2 and 0<=v<=1.



The Attempt at a Solution



I have no idea how to tackle this. Any suggestions?
 
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bugatti79 said:

Homework Statement



Evlute the surface integral

Homework Equations



f(x,y,z)=x+y+z where sigma is the parallelogram with parametric equations x=u+v, y=u-v and z=1+2u+v where 0 <=u<=2 and 0<=v<=1.



The Attempt at a Solution



I have no idea how to tackle this. Any suggestions?

You might begin by studying the material at:

http://tutorial.math.lamar.edu/Classes/CalcIII/SurfaceIntegrals.aspx
 
LCKurtz said:
You might begin by studying the material at:

http://tutorial.math.lamar.edu/Classes/CalcIII/SurfaceIntegrals.aspx

I believe we have to use [itex]\displaystyle \int \int _R f(x(u,v),y(u,v), z(u,v) || r_u \times r_v||dA[/itex]

I calculate the magnitude of the determinent to be \sqrt 2 hence

The surface integral becomes

[itex]\displaystyle \sqrt{2} \int_{0}^{1} \int_{0}^{2} (4u+v+1) du dv[/itex]...?
 
I agree with everything except the ##\sqrt 2##.
 
LCKurtz said:
I agree with everything except the ##\sqrt 2##.

since we have the determinant as 3i+1j-2k and the magnitude is

[itex]\sqrt(3^2+(-2^2)+1)=\sqrt 14[/itex] cheers
 
bugatti79 said:
since we have the determinant as 3i+1j-2k and the magnitude is

[itex]\sqrt(3^2+(-2^2)+1)=\sqrt 14[/itex] cheers

The ##\sqrt {14}## is correct, but 3i + j - 2k is not a determinant; it is a vector.
 

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