- #1
sapiental
- 118
- 0
evaluate the indefinite integral cos^4(x)sin(x)dx
I tried using the half angle formula but this gives me a much more difficult integral, so i resorted to just regular substitution but am not sure if I can do this.
u = cos(x)
du = -sin(x)dx
indefinite integral -u^4du
then -1/5(u)^5 + C or -1/5(cos^5) + C
thanks!
I tried using the half angle formula but this gives me a much more difficult integral, so i resorted to just regular substitution but am not sure if I can do this.
u = cos(x)
du = -sin(x)dx
indefinite integral -u^4du
then -1/5(u)^5 + C or -1/5(cos^5) + C
thanks!