Evaluating Complex Integrals Using Cauchy's Integral Formula

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Homework Help Overview

The discussion revolves around evaluating complex integrals using Cauchy's integral formula, specifically for integrals over different circular paths in the complex plane.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Cauchy's integral formula with specific functions and points, questioning how to adapt their approach for different radii of integration circles.
  • Some participants question the inclusion of specific points within the integration contours and the implications for the integral's value.
  • There is a discussion about the relevance of the integral theorem and its application to the problem at hand.
  • One participant expresses confusion regarding the interpretation of the denominator in the integral and its effect on the integration path.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and clarifying the conditions under which Cauchy's integral formula applies. Some guidance has been provided regarding the necessity of including specific points within the integration contour.

Contextual Notes

Participants are navigating the implications of different circular paths in relation to the points involved in the integrals, highlighting the importance of visualizing the curves and their relationships to the points of interest.

AlBell
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Homework Statement



Use Cauchy's integral formula to evaluate
34t8wo3.png
when
a) C is the unit circle
b) c is the circle mod(Z)=2

Homework Equations



I know the integral formula is
14mtco.png



The Attempt at a Solution


for the unit circle I was attempting F(z)=sin(z) and Z0=∏/2, which would give a solution of 2∏i, however if this is the correct method I am unsure how to modify it for a larger unit circle as I thought the final result was independent of radius
 
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The integral formula requires the point z0 to be contained inside of the curve gamma that you are integrating around. Draw some pictures and you should see the difference between the two curves they are asking you to integrate on
 
Ah so the unit circle wouldn't actually contain the point pi/2 whereas the circle mod(z)=2 would?
 
That's right. So in the unit circle case you need to figure out something else that let's you calculate the integral
 
Can I then use the integral theorem that says it will equal 0?
 
That will work
 
I'm a bit confused again, sorry!
I thought that the z-Pi/2 on the denominator of the integral means we just shift the origin of the circle to a new position?
 

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