Evaluating Limit of Expanded e^x: 0?

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    E^x Limit
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Homework Statement



&space;}\frac{x^{n}}{e^{x}}&space;=&space;\lim_{n&space;\to&space;\infty&space;}\frac{n!}{e^{x}}.gif


I tried expanding e^x and evaluated the limit as 1.
The answer given is 0.
 
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How odd. The answer actually depends on the values of x... try a couple of values of x and you'll see what I mean. Might I recommend .75 and 2?
 


This question is actually a part of another one.

space;Hospitals&space;rule,&space;n&space;times&space;for&space;}\&space;\frac{x^{n}}{e^{x}}.....gif


Got any idea now?
 


Either there's a typo or you misread it. It should be as [tex]x\to\infty[/tex]. Then it makes sense, especially since you're integrating over dx, not over dn.
 


Oh yes, that must be a typo. I got it now.
Thanks!