Evaluating Limits using L'Hospital (2)

[shamieh]

lim x--> 1
$$
\frac{x^4 - 3x^3 + 3x^2 - x}{x^4 - 2x^3 + 2x - 1}$$I got $$\frac{0}{6} = 0$$

 

[MarkFL]

That's incorrect. Since you showed no work, I can't tell you where you went wrong. I will tell you I applied L'Hôpital's Rule 3 times to get the value of the limit.

 

[shamieh]

re did the problem, didn;t take the deriv properly in the denom. Did you get $$\frac{-1}{4}$$

 

[MarkFL]

No, that's no what I got either (and I verified my result using a CAS). If you show your work, I can address where you are going wrong. :D

 

[shamieh]

wow I'm a idiot. I put 24 - 12 = 24... -_-... I got $$\frac{1}{2}$$ .. correct?

 

[MarkFL]

wow I'm a idiot. I put 24 - 12 = 24... -_-... I got $$\frac{1}{2}$$ .. correct?

Yes, that's correct.