Evaluating logarithms given log(a)b = 3

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The discussion centers on evaluating the expression 4log(a)(1/b) + 2log(a)b^3 given that log(a)b = 3. The user applies logarithmic properties, including log(a)1 = 0 and the rules for logarithms of products and powers. Their calculations lead to the final result of 6. Other participants confirm the correctness of this solution. The evaluation demonstrates a proper application of logarithmic rules to derive the answer.
zebra1707
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Hi there

Can someone please review my work and advise.

Homework Statement



Given log(a)b=3 , use the properties of logs to evaluate

4log(a)(1/b)+2log(a)b^3

Homework Equations



I used the rules

log(a)1 = 0

log(a)(x/y) = log(a)x-log(a)y

log(a)x^m = mlog(a)x

The Attempt at a Solution



=4loga1-4logab+2logab^3
=-12+6*3
=-12+18
=6
 
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zebra1707 said:
Hi there

Can someone please review my work and advise.

Homework Statement



Given log(a)b=3 , use the properties of logs to evaluate

4log(a)(1/b)+2log(a)b^3

Homework Equations



I used the rules

log(a)1 = 0

log(a)(x/y) = log(a)x-log(a)y

log(a)x^m = mlog(a)x

The Attempt at a Solution



=4loga1-4logab+2logab^3
=-12+6*3
=-12+18
=6
That is correct !
 
SammyS said:
That is correct !

Thank you for your assistance.
 

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