Evaluating Repeated Integral: cos y sin x

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SUMMARY

The discussion focuses on evaluating the repeated integral of the function cos(y) sin(x) over the specified limits. The integral is expressed as y=0π/2x=yπ/2 cos(y) sin(x) dx dy. The solution involves iterating the integration process, specifically calculating x=yπ/2 sin(x) dx to simplify the overall evaluation. The participants emphasize the importance of integration by iteration in solving such problems.

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  • Understanding of repeated integrals
  • Familiarity with trigonometric functions, specifically sin(x) and cos(y)
  • Knowledge of integration techniques, particularly integration by parts
  • Basic calculus concepts, including limits of integration
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Evaluate the following repeated integral:
[Pi/2]\int[/0][Pi/2]\int[/y]cos y sin x dx dy
 
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Have you ever encountered integration by iteration?

Also, you need to show your attempt at a solution.
 
This is
\int_{y=0}^{\pi/2}\int_{x= y}^{\pi/2}cos(y) sin(x)dy dx
= \int_{y= 0}^{\pi/2}cos(y)\left(\int_{x= y}^{2\pi} sin(x)dx\right)dy

Now, what is
\int_{x= y}^{\pi/2} sin(x)dx?
 

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