Evaluating the Elapsed Time Difference Between Clocks in a Gravitational Field

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MeJennifer
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Clocks show less elapsed time in gravitational field right?
So clocks on Earth seem to apply.

Consider one clock stationed on the north pole and one somewhere on the equator, both at sea level.

It seems there are a couple of factors in order to calculate the difference in time between each clock and a fictional observer in flat space.

Looks like we have to take into consideration the following things

They are in a gravitational field
The EM-force accelerates in the opposite direction
The Earth is rotating,
Both clocks are accelerating due to the rotation (each one slightly different).
The Earth is not a perfect sphere.

My main question concerning this problem is the "cancellation" of the EM-force. How does the EM force interact with the curvature? Are there well established theories for this?
 
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It's somewhat well known that all clocks on the geoid (intuitively, at sea leve) tick at the same rate.

I'm not sure what your concerns with the "EM field" are. You don't need to know the acceleration of a clock to know how it keeps time - you only need to know the metric, and the velocity of the clock.