MHB Evaluating the indefinite integral.

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The integral $$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$ simplifies to $$\ln(x^2 + 2x + 5)$$ through the substitution $$u = x^2 + 2x + 5$$, leading to $$du = (2x + 2)dx$$, which transforms the integral into $$\int \frac{1}{u} \, du$$. The discussion highlights that the absolute value signs in the logarithmic result are not necessary since the expression $$x^2 + 2x + 5$$ is always positive for real x. While some argue that including absolute values is technically correct, others advocate for mathematical simplicity by omitting them. Ultimately, both forms are valid, but the preference is for the simpler expression without absolute values.
shamieh
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How does

$$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$ turn into $$\ln(x^2 + 2x + 5)$$?

How are they getting rid of the numerator are they just dividing by the reciprocal of 2x + 2?
 
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The simplest thing to do is use the substitution:

$$u=x^2+2x+5\,\therefore\,du=(2x+2)\,dx$$

And now you have:

$$\int\frac{1}{u}\,du$$
 
Hmm, this was the result of a partial fraction decomposition problem, I guess after solving three formulas a u substitution just seemed to simple (Tauri)(Dance)
 
$$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$ turn into $$\ln(x^2 + 2x + 5)$$?

Solution:: Given $\displaystyle \int\frac{2x+2}{x^2+2x+5}dx$

Let $x^2+2x+5 = t$, Then $\left(2x+2\right)dx = dt$

So Integral convert into $\displaystyle \int\frac{1}{t}dt = \ln \left|t\right|+\mathbb{C}$

So $\displaystyle \int\frac{2x+2}{x^2+2x+5}dx = \ln \left|x^2+2x+5\right|+\mathbb{C}$
 
My teacher has the solution has $$\ln(x^2 + 2x + 5)$$ without the abs value signs...Do you think it's a typo on his part or is there any particular reasons I shouldn't put the abs value sign?
 
shamieh said:
My teacher has the solution has $$\ln(x^2 + 2x + 5)$$ without the abs value signs...Do you think it's a typo on his part or is there any particular reasons I shouldn't put the abs value sign?

Complete the square:

$$x^2+2x+5=(x+1)^2+2^2>0$$ for all real $x$ so the absolute value signs are not necessary in this case. Your teacher is correct. :D
 
With that being said, do you think I would get points taken off for just leaving it with the absolute value signs?
 
shamieh said:
With that being said, do you think I would get points taken off for just leaving it with the absolute value signs?

Well, I can't speak for your professor, but technically either is correct. I don't think I would deduct points personally, however in my mind I would certainly favor the response that shows recognition of the fact that the expression is never negative for any real $x$.

However, let's put aside the notion of point deduction and look instead at the issue of mathematical simplicity and elegance. I think there is something to be said for striving to make our results as simple as possible while still covering all cases. I see putting absolute value signs around an expression that is always non-negative as a form of kludge. I think we should look at such things and remove anything that is unnecessary, so that our results are as lean as possible. (Wink)
 

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