Evaluating the indefinite integral.

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Discussion Overview

The discussion revolves around the evaluation of the indefinite integral $$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$, exploring methods of integration, particularly substitution and the use of logarithmic functions. Participants also examine the necessity of absolute value signs in the final expression.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests using the substitution $$u=x^2+2x+5$$, leading to the integral $$\int\frac{1}{u}\,du$$.
  • Another participant notes that the integral can be transformed into $$\int\frac{1}{t}dt = \ln \left|t\right|+\mathbb{C}$$ using a similar substitution.
  • There is a discussion about whether to include absolute value signs in the final answer, with one participant stating that the expression $$x^2 + 2x + 5$$ is always positive for real $x$, thus making the absolute value unnecessary.
  • Another participant questions if they would lose points for including absolute value signs, with a response indicating that both forms are technically correct but suggesting a preference for simplicity.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of absolute value signs in the final expression. While some argue that they are not needed due to the positivity of the expression, others maintain that including them is technically correct. No consensus is reached on this point.

Contextual Notes

Participants discuss the implications of including absolute value signs based on the positivity of the expression derived from completing the square. The discussion reflects varying opinions on mathematical elegance versus technical correctness.

shamieh
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How does

$$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$ turn into $$\ln(x^2 + 2x + 5)$$?

How are they getting rid of the numerator are they just dividing by the reciprocal of 2x + 2?
 
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The simplest thing to do is use the substitution:

$$u=x^2+2x+5\,\therefore\,du=(2x+2)\,dx$$

And now you have:

$$\int\frac{1}{u}\,du$$
 
Hmm, this was the result of a partial fraction decomposition problem, I guess after solving three formulas a u substitution just seemed to simple (Tauri)(Dance)
 
$$\int \frac{2x + 2}{x^2 + 2x + 5} \, dx$$ turn into $$\ln(x^2 + 2x + 5)$$?

Solution:: Given $\displaystyle \int\frac{2x+2}{x^2+2x+5}dx$

Let $x^2+2x+5 = t$, Then $\left(2x+2\right)dx = dt$

So Integral convert into $\displaystyle \int\frac{1}{t}dt = \ln \left|t\right|+\mathbb{C}$

So $\displaystyle \int\frac{2x+2}{x^2+2x+5}dx = \ln \left|x^2+2x+5\right|+\mathbb{C}$
 
My teacher has the solution has $$\ln(x^2 + 2x + 5)$$ without the abs value signs...Do you think it's a typo on his part or is there any particular reasons I shouldn't put the abs value sign?
 
shamieh said:
My teacher has the solution has $$\ln(x^2 + 2x + 5)$$ without the abs value signs...Do you think it's a typo on his part or is there any particular reasons I shouldn't put the abs value sign?

Complete the square:

$$x^2+2x+5=(x+1)^2+2^2>0$$ for all real $x$ so the absolute value signs are not necessary in this case. Your teacher is correct. :D
 
With that being said, do you think I would get points taken off for just leaving it with the absolute value signs?
 
shamieh said:
With that being said, do you think I would get points taken off for just leaving it with the absolute value signs?

Well, I can't speak for your professor, but technically either is correct. I don't think I would deduct points personally, however in my mind I would certainly favor the response that shows recognition of the fact that the expression is never negative for any real $x$.

However, let's put aside the notion of point deduction and look instead at the issue of mathematical simplicity and elegance. I think there is something to be said for striving to make our results as simple as possible while still covering all cases. I see putting absolute value signs around an expression that is always non-negative as a form of kludge. I think we should look at such things and remove anything that is unnecessary, so that our results are as lean as possible. (Wink)
 

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