Evaluation of work in thermodynamics

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Homework Help Overview

The discussion revolves around evaluating the work done during a thermodynamic transformation of a monoatomic ideal gas in a cylinder with a sliding piston. The transformation involves a change in volume from VA to VB, with the condition that the product of volume and pressure squared remains constant.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to express pressure as a function of volume during the transformation, questioning which pressure value to use in the work integral. There is an attempt to derive relationships between the initial and final states of the gas.

Discussion Status

Participants are actively engaging with the problem, with some providing equations to express the relationship between pressure and volume. There is a recognition of the need to integrate pressure over the volume change, and guidance is being offered on how to set up the integral correctly.

Contextual Notes

There is an emphasis on the non-constant nature of pressure during the transformation, and participants are working within the constraints of known values for PA and VA while seeking to derive expressions for PB and the work done.

DottZakapa
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Inside a cylinder with a sliding piston, n mole of monoatomic ideal gas at temperature TA occupy a volume VA at pressure PA, in equilibrium. The piston is expanded very slowly, turning the pressure in such a way that the product V⋅P2 remains constant till the volume VB .

I have to evaluate the work in the transformation from A to B:
VB = 4 VA
PA and VA are known

wAB = ∫ P⋅dV =

My question is:
- Which value of Pressure shall I insert instead of P considering the fact that it isn't constant during the transformation?
 
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If VP2 remains constant, it must be equal to VP2 in state A. Can you write an equation to express this in terms of PA and VA?

Chet
 
DottZakapa said:
My question is:
- Which value of Pressure shall I insert instead of P considering the fact that it isn't constant during the transformation?
Express P as a function of V.
 
VA⋅PA2=VB⋅PB2
Then
PA=(VB½⋅PB)/VA½
and then I substitute in the integral:
∫ (VB½⋅PB)/VA½ dV

is it ?
 
DottZakapa said:
VA⋅PA2=VB⋅PB2
Then
PA=(VB½⋅PB)/VA½
and then I substitute in the integral:
∫ (VB½⋅PB)/VA½ dV

is it ?
Not exactly. VP2=VAPA2

Solve for P and then integrate PdV between VA and VB.
 
Aw ok! now i get it.
Thank you very much for your time. Very helpful.
Have a nice day : )
 

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