Every field is an integral domain?

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    Domain Field Integral
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SUMMARY

The discussion centers on the properties of integral domains, specifically addressing the statement that if the product of two elements \( r \) and \( s \) in a ring \( R \) equals zero (i.e., \( rs = 0 \)), then at least one of the elements must be zero. Participants clarify that the assumption that both \( r \) and \( s \) have multiplicative inverses is incorrect if either is zero. The conclusion is that the original assertion holds true, but the logic presented by the user misapplies the concept of inverses in the context of zero elements.

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PsychonautQQ
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Okay, so if r,s are elements of R and rs = 0 then either r or s has to equal zero.

I'm just confused because it seems that if rs = 0 then we can show that both r and s must be zero... I don't know what I'm doing wrong..

rs = 0
r^-1(rs) = r^-1(0) = 0
1s = 0
s = 0

and then:

rs = 0
r(ss^-1) = (0)s^-1 = 0
r1 = 0 = 0
r = 0

I mean, both r and s have multiplicative inverses so it seems like r and s both need to be zero by this logic.. what am i doing wrong here?
 
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PsychonautQQ said:
I mean, both r and s have multiplicative inverses
Not if they are zero.

5*0=0 in the real numbers
Now try to apply your prove to show 5=0. It won't work.
 
PsychonautQQ said:
Okay, so if r,s are elements of R and rs = 0 then either r or s has to equal zero.

I'm just confused because it seems that if rs = 0 then we can show that both r and s must be zero... I don't know what I'm doing wrong..

rs = 0
r^-1(rs) = r^-1(0) = 0
You are assuming, when you write this, that r has an inverse. Which is only true if r is not 0.
1s = 0
s = 0
So what you have proved is "if r is not 0 then s is 0"

and then:

rs = 0
r(ss^-1) = (0)s^-1 = 0
r1 = 0 = 0
r = 0
again, you have proved that "if s is not 0 then r is 0".

I mean, both r and s have multiplicative inverses
no, this is not true.
so it seems like r and s both need to be zero by this logic.. what am i doing wrong here?
 
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