Evolution of temperature (adiabatic procsses)

[ted1986]

Hello,

I'm trying to derive a differential equation as requested in the attached exercise (thermal1.jpg).
I'm not quite sure my solution is the right answer (my_solution1.jpg).
How do I get rid of the energy dU ?

Thnks


Ted

 

[sgd37]

well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation

 

[ted1986]

well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation

OK, It sure gives a simple derivation of the differential equation, but what is the physical explanation for that?

Thanks

 

[sgd37]

it most generally means that it is a reversible process