Evolution of temperature (adiabatic procsses)

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SUMMARY

The discussion centers on deriving a differential equation related to adiabatic processes, specifically addressing the relationship between energy changes and entropy. Ted inquires about eliminating the energy term dU from his solution. The response clarifies that in adiabatic processes, the heat transfer dQ equals zero, leading to a simplification where the change in entropy ds also equals zero. This indicates that the process is reversible.

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ted1986
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Hello,

I'm trying to derive a differential equation as requested in the attached exercise (thermal1.jpg).
I'm not quite sure my solution is the right answer (my_solution1.jpg).
How do I get rid of the energy dU ?

Thnks


Ted
 

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well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation
 
sgd37 said:
well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation


OK, It sure gives a simple derivation of the differential equation, but what is the physical explanation for that?

Thanks
 
it most generally means that it is a reversible process
 

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