- #1
bob012345
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- I believe it may be impossible but has anyone seen or come across an exact expression of the sin of 1 degree in a closed form that does not involve either complex roots, infinite series, or sines and cosines of other angles. Thanks.
For example, $$Sin(15)= \frac {(\sqrt 6 - \sqrt 2)} 4$$
and $$Sin(3)=\frac {(\sqrt 6 (\sqrt 5 -1)(3+\sqrt 3)} {48} -\frac {\sqrt 3 (3-\sqrt 3 )\sqrt{ 5+\sqrt 5 }} {24}$$
What about ##Sin(1)##?
and $$Sin(3)=\frac {(\sqrt 6 (\sqrt 5 -1)(3+\sqrt 3)} {48} -\frac {\sqrt 3 (3-\sqrt 3 )\sqrt{ 5+\sqrt 5 }} {24}$$
What about ##Sin(1)##?