Example of x0 in the kinematic equation for displacement

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Discussion Overview

The discussion revolves around the kinematic equation for displacement, specifically focusing on the initial position variable, x0, and its possible values in different scenarios of motion. Participants explore examples involving both vertical and horizontal motion, examining how the choice of origin affects the value of x0.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant asks for an example where x0 is not zero in the kinematic equation x = x0 + v0 * t + .5 * a * t^2.
  • Another participant explains that x0 represents the initial position and can be any value, providing an example of dropping an object from a height of 5 meters, where x0 = 5 m and v0 = 0 m/s.
  • A participant requests an example where both x and x0 are not zero.
  • One participant clarifies that x(t) changes over time and will be non-zero until the particle hits the ground in the vertical example provided.
  • A request is made for a horizontal motion example where both x and x0 are not zero.
  • Another participant suggests starting a particle 5 meters from the origin with an initial velocity of 5 m/s in the horizontal direction.
  • One participant reflects on the confusion regarding whether x0 should be zero, indicating it depends on the context of the problem.
  • A later reply emphasizes that the choice of origin determines the value of x0, illustrating this with the previous example of dropping an object from a height.

Areas of Agreement / Disagreement

Participants generally agree that the value of x0 can vary based on the chosen origin of the coordinate system. However, there is some confusion regarding when to set x0 to zero, indicating that the discussion remains somewhat unresolved.

Contextual Notes

Participants note that the choice of origin can significantly affect the values of x0 and x, and that different scenarios may lead to different interpretations of these variables.

e-zero
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In the kinematic equation x = x0 + v0 * t + .5 * a * t^2, can someone give me an example in which x0 has a value that is not zero?
 
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Hi e-zero! ##x_{0}## is just the initial position of the test particle that you are looking at the trajectory of under constant acceleration; similarly ##v_{0}## is just the initial velocity of the trajectory. You can choose them to be whatever you want them to be. I can for example drop my object from a height of 5 meters from the ground, starting at rest, in which case ##x_{0} = 5 \text{m}## , ##v_{0} = 0 \text{m /s}## , and (ignoring air resistance) the equations of motion become ##x(t) = 5 \text{m} - \frac{1}{2}gt^{2}##. Hope that helps friend!
 
Ok, is there an example where both x and x0 are both not zero?
 
##x(t)## is a function of time so it will change its value at every instant of time. In the example I gave above, ##x(t)## is the height of the particle from the ground so it will be non-zero up until the first time the particle hits the ground.
 
Can you give an example that does not involve vertical, but horizontal motion in which x and x0 are both not zero?
 
Sure! Choose an origin and take a particle located 5 meters horizontally from that origin and give it an initial kick of 5 meters per second in the horizontal direction.
 
Ok. I was just confusing myself. It all depends on the question if you should take x0 to be zero or not.
 
Indeed! Good luck with your studies friend :)
 
Thanks
 
  • #10
e-zero said:
Ok. I was just confusing myself. It all depends on the question if you should take x0 to be zero or not.

Not really. It depends on where you want the origin of your system of coordinates to be. In WBN's example, he chose the ground as origin. That's why x_0 in his case was 5m. For the same example he could have chosen its origin 5 meters above the ground, in which case x_0 would have been 0.
 
  • #11
Ok, I see.
 

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