Expand Harmonic Potential in Taylor Series | Piz

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SUMMARY

The discussion centers on the application of Taylor series to expand harmonic potential. Participants confirm that while it is theoretically possible to use a Taylor series for harmonic potential, it is largely unnecessary since the harmonic potential is already represented by the second term in the series. The conversation also highlights the utility of Taylor's theorem in approximating complex potentials, particularly those involving trigonometric functions, around specific points. A key point raised is the challenge of applying Taylor's theorem to functions that are not explicitly defined, such as certain potential functions.

PREREQUISITES
  • Understanding of Taylor's theorem and its mathematical implications
  • Familiarity with harmonic potential in physics
  • Knowledge of differentiable functions and their approximations
  • Basic grasp of trigonometric functions and their series expansions
NEXT STEPS
  • Research the derivation and applications of Taylor's theorem in physics
  • Explore examples of Taylor series expansions for trigonometric functions
  • Study the concept of harmonic potential in classical mechanics
  • Investigate the limitations of Taylor series for non-explicit functions
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Students in physics or mathematics, particularly those studying classical mechanics, as well as educators and researchers interested in the application of Taylor series in potential theory.

SANGHERA.JAS
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Can we expand harmonic potential in a Taylor series. If so then piz tell me how?
 
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Yes, but it would be rather pointless since the expression for the potential is already identical to the second term in the taylor expansion.

The harmonic potential is as simple as it gets, I can't think of any reason why you would want to use a series expansion of any kind; at least not if you are trying to simplify the calculation.
 
But the third term in that series IS the harmonic potential...
For an harmonic potential all the other terms are -by definition- zero.

Maybe I've misunderstood your question?
 
You are somewhat right my friend. But my actual question is: From where the series itself come about?Although I understand Taylor's theorem well, but I am still not getting it?
 
Now, that is a complettely different question.
Although I am still not quite sure exactly what it is you do not understand.

Do you understand how one can use a Taylor series to approximate any differentiable function (such as an exponential) around some point? I.e do you understand the math?

Have you for example looked a the wiki for Taylor's theorem?
http://en.wikipedia.org/wiki/Taylor's_theorem

The reason why the theorem is so useful in physics is that it allows us to expand a complicated potential (a common example would be a potential that contains trigonometric functions) around some point we are interested in.
For many potentials of interest you can get a good approximation by truncating the series after the third term, meaning all you end up with is the harmonic potential which is easy to deal with.
 
My friend I am a second year bachelor student; so I understand mathematics and hence Taylor's theorem very well. But my question is we use Taylor's expansion in case of function which are explicitly given e.g. sine, cosine, exponential, {1/(1-x^2)} etc. But how can we use Taylor's theorem in case of functions which are not explicitly given; that is the case when we talk about potential function, In this case neither the function itself nor the exact dependence on any sort of variable is given.
 

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