Expanding ln isn't working for me

[iScience]

original equation: ln(0.2048x^\frac{5}{2})= -\frac{5}{2}

when i just raise this to e i get..

0.2048T^\frac{5}{2}= -\frac{5}{2}

and then i can solve for x and get the right answer. but when i expand the logs..

ln(0.2048) + \frac{5}{2}ln(x)= -\frac{5}{2}

0.2048+\frac{5}{2}x=e^-\frac{5}{2}

then i try to solve for x i don't get the right answer. what am i doing wrong?

 

[Pythagorean]

you can't do that with a sum of ln's. Taking the exponent of both sides after expansion does not cancel out the ln in each term. You would have e^(lnA + lnB) and that does not equal A+B.

 

[iScience]

oops, lol thanks

 

[Pythagorean]

no problem