Expanding triple (cross) product

Click For Summary
SUMMARY

The discussion focuses on expanding the triple product L = mr x (ω x r) using the bac-cab rule, specifically addressing the case when vector r is perpendicular to vector ω. Participants clarify that the correct application of the bac-cab rule leads to the expression L = m[r²ω - (ω·r)r]. The confusion arises from the distribution of terms and the simplification of dot products, particularly the scalar nature of ω·r. Ultimately, the correct simplification yields the elementary formula for angular momentum, L = mvr.

PREREQUISITES
  • Understanding of vector operations, specifically cross and dot products.
  • Familiarity with the bac-cab rule for vector expansion.
  • Knowledge of angular momentum concepts in physics.
  • Ability to manipulate and simplify vector equations.
NEXT STEPS
  • Study the bac-cab rule in detail to master vector expansions.
  • Learn about vector dot products and their geometric interpretations.
  • Explore angular momentum in classical mechanics, focusing on its derivation and applications.
  • Practice problems involving vector identities and simplifications in physics.
USEFUL FOR

Students of physics, particularly those studying classical mechanics, as well as educators and tutors looking to clarify vector operations and angular momentum concepts.

leroyjenkens
Messages
616
Reaction score
49

Homework Statement



Use (the bac-cab rule) to expand this triple product:L = mr x (ω x r)

If r is perpendicular to ω, show that you obtain the elementary formula, angular momentum = mvr.

(The bold letters are vectors.)

Homework Equations



A X (B X C) = (A\cdotC)B - (A\cdotB)C

The Attempt at a Solution



Well, simply doing the bac-cab rule, I get

(mr \cdotω)r - (mr \cdotr)ω

Which isn't even close to the answer in the book, which is:

L=m[r2ω-(ω \cdotr)r]

No idea how they got that.

Even if I distribute the r, they don't have it distributed to the ω, and on the right term, they don't distribute the ω. I don't understand.
Thanks
 
Physics news on Phys.org
leroyjenkens said:

The Attempt at a Solution



Well, simply doing the bac-cab rule, I get

(mr \cdotω)r - (mr \cdotr)ω
This is wrong, going by the rule we get
m[(r.r)ω-(r.ω)r]
On simplification we'll get the answer...
Regards
 
Abhilash H N said:
This is wrong, going by the rule we get
m[(r.r)ω-(r.ω)r]
On simplification we'll get the answer...
Regards

OK yeah I lost track of which one was A, B, and C.

But this is what I get:
(mr\cdotr)ω-(mr\cdotω)r

r\cdotr simplifies to r2 because it's the vector dotted into itself, which produces the magnitude of that vector squared?

And according to the solution, why didn't they distribute the r through the parentheses in the second term?

Thanks.
 
What specifically do you mean by "distribute the r through the parentheses"?
 
vela said:
What specifically do you mean by "distribute the r through the parentheses"?

Oh ok, so that r isn't allowed to go into the parentheses until the r is dotted into the ω?
 
I guess I still don't know what you're trying to do. ##\vec{\omega}\cdot\vec{r}## is a scalar, and the result of the product multiplies ##\vec{r}##. By pulling ##\vec{r}## into the parentheses, what do you intend to accomplish?
 

Similar threads

Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
998
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K