Where did the blue box vector come from in the vector multiplication problem?

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influx
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Homework Statement


Handwritten-style derivation of a vector triple product: a cross product of omega with (omega cross r_AO) expanded into a 3x3 determinant with unit vectors i, j, k, ending in a simplified vector expression.


Homework Equations



RAO = b(Sinβj+Cosβk)

The Attempt at a Solution


[/B]
The box in red is ω. However I am unsure of where they got the box in blue from? As mentioned above, RAO = b(Sinβj+Cosβk) so not sure where they got the box in blue from? I know of the vector triple product: A x (B x C) = (A•C)B - (A.B)C, but this isn't what they've done?

Thanks
 
influx said:

Homework Statement


Vector cross product worked out by hand: omega cross (omega cross r_AO) = b times a red-boxed vector cross a blue-boxed vector, then a 3x3 determinant with i, j, k columns, and a simplified result in terms of beta, p, Omega.


Homework Equations



RAO = b(Sinβj+Cosβk)

The Attempt at a Solution


[/B]
The box in red is ω. However I am unsure of where they got the box in blue from? As mentioned above, RAO = b(Sinβj+Cosβk) so not sure where they got the box in blue from? I know of the vector triple product: A x (B x C) = (A•C)B - (A.B)C, but this isn't what they've done?

Thanks

I would assume that they are doing the obvious thing, ie. calculating [itex]\mathbf{\omega} \times \mathbf{r}_{AO}[/itex] first, and given the presence of a scalar factor of [itex]b[/itex] (which goes missing in the second line before reappearing in the third) the vector in the blue box must therefore be [tex]\frac{\mathbf{\omega} \times \mathbf{r}_{AO}}{b}.[/tex] (Although given that something did go missing partway through I would recommend double-checking this.)
 
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